pairs with difference k coding ninjas github

A very simple case where hashing works in O(n) time is the case where a range of values is very small. Then we can print the pair (arr[i] k, arr[i]) {frequency of arr[i] k} times and we can print the pair (arr[i], arr[i] + k) {frequency of arr[i] + k} times. No description, website, or topics provided. Given an unsorted integer array, print all pairs with a given difference k in it. //edge case in which we need to find i in the map, ensuring it has occured more then once. (5, 2) // Function to find a pair with the given difference in the array. pairs with difference k coding ninjas github. Below is the O(nlgn) time code with O(1) space. The following line contains an integer, that denotes the value of K. The first and only line of output contains count of all such pairs which have an absolute difference of K. public static int getPairsWithDifferenceK(int arr[], int k) {. (5, 2) CodingNinjas_Java_DSA/Course 2 - Data Structures in JAVA/Lecture 16 - HashMaps/Pairs with difference K Go to file Cannot retrieve contributors at this time 87 lines (80 sloc) 2.41 KB Raw Blame /* You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. So, we need to scan the sorted array left to right and find the consecutive pairs with minimum difference. We are sorry that this post was not useful for you! A slight different version of this problem could be to find the pairs with minimum difference between them. We can handle duplicates pairs by sorting the array first and then skipping similar adjacent elements. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. We can improve the time complexity to O(n) at the cost of some extra space. Program for array left rotation by d positions. Coding-Ninjas-JAVA-Data-Structures-Hashmaps/Pairs with difference K.txt Go to file Go to fileT Go to lineL Copy path Copy permalink This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. The algorithm can be implemented as follows in C++, Java, and Python: Output: 3. * Iterate through our Map Entries since it contains distinct numbers. HashMap map = new HashMap<>(); System.out.println(i + ": " + map.get(i)); //System.out.println("Current element: "+i); //System.out.println("Need to find: "+(i-k)+", "+(i+k)); countPairs=countPairs+(map.get(i)*map.get(k+i)); //System.out.println("Current count of pairs: "+countPairs); countPairs=countPairs+(map.get(i)*map.get(i-k)). In file Main.java we write our main method . No votes so far! If nothing happens, download Xcode and try again. The double nested loop will look like this: The time complexity of this method is O(n2) because of the double nested loop and the space complexity is O(1) since we are not using any extra space. 2) In a list of . sign in Then (arr[i] + k) will be equal to (arr[i] k) and we will print our pairs twice! Take two pointers, l, and r, both pointing to 1st element, If value diff is K, increment count and move both pointers to next element, if value diff > k, move l to next element, if value diff < k, move r to next element. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. The second step runs binary search n times, so the time complexity of second step is also O(nLogn). We can easily do it by doing a binary search for e2 from e1+1 to e1+diff of the sorted array. You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. Work fast with our official CLI. Therefore, overall time complexity is O(nLogn). Cannot retrieve contributors at this time 72 lines (70 sloc) 2.54 KB Raw Blame He's highly interested in Programming and building real-time programs and bots with many use-cases. Follow me on all Networking Sites: LinkedIn : https://www.linkedin.com/in/brian-danGitHub : https://github.com/BRIAN-THOMAS-02Instagram : https://www.instagram.com/_b_r_i_a_n_#pairsum #codingninjas #competitveprogramming #competitve #programming #education #interviewproblem #interview #problem #brianthomas #coding #crackingproblem #solution Inside file Main.cpp we write our C++ main method for this problem. Inside file PairsWithDiffK.py we write our Python solution to this problem. // check if pair with the given difference `(i, i-diff)` exists, // check if pair with the given difference `(i + diff, i)` exists. System.out.println(i + ": " + map.get(i)); for (Integer i: map.keySet()) {. This is O(n^2) solution. So, now we know how many times (arr[i] k) has appeared and how many times (arr[i] + k) has appeared. * Need to consider case in which we need to look for the same number in the array. (5, 2) * We are guaranteed to never hit this pair again since the elements in the set are distinct. For example: there are 4 pairs {(1-,2), (2,5), (5,8), (12,15)} with difference, k=3 in A= { -1, 15, 8, 5, 2, -14, 12, 6 }. Enter your email address to subscribe to new posts. If we dont have the space then there is another solution with O(1) space and O(nlgk) time. Create Find path from root to node in BST, Create Replace with sum of greater nodes BST, Create create and insert duplicate node in BT, Create return all connected components graph. You signed in with another tab or window. Take two pointers, l, and r, both pointing to 1st element. Method 5 (Use Sorting) : Sort the array arr. Find pairs with difference k in an array ( Constant Space Solution). Learn more about bidirectional Unicode characters. Please Learn more about bidirectional Unicode characters. To review, open the file in an editor that reveals hidden Unicode characters. Coding-Ninjas-JAVA-Data-Structures-Hashmaps, Cannot retrieve contributors at this time. Are you sure you want to create this branch? We run two loops: the outer loop picks the first element of pair, the inner loop looks for the other element. Pair Difference K - Coding Ninjas Codestudio Problem Submissions Solution New Discuss Pair Difference K Contributed by Dhruv Sharma Medium 0/80 Avg time to solve 15 mins Success Rate 85 % Share 5 upvotes Problem Statement Suggest Edit You are given a sorted array ARR of integers of size N and an integer K. There was a problem preparing your codespace, please try again. Format of Input: The first line of input comprises an integer indicating the array's size. But we could do better. We also need to look out for a few things . Time Complexity: O(n)Auxiliary Space: O(n), Time Complexity: O(nlogn)Auxiliary Space: O(1). Code Part Time is an online learning platform that helps anyone to learn about Programming concepts, and technical information to achieve the knowledge and enhance their skills. Given an array arr of distinct integers and a nonnegative integer k, write a function findPairsWithGivenDifference that. To review, open the file in an. The time complexity of the above solution is O(n.log(n)) and requires O(n) extra space, where n is the size of the input. The first line of input contains an integer, that denotes the value of the size of the array. to use Codespaces. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. (4, 1). Time Complexity: O(n2)Auxiliary Space: O(1), since no extra space has been taken. Inside this folder we create two files named Main.cpp and PairsWithDifferenceK.h. O(nlgk) time O(1) space solution The idea is that in the naive approach, we are checking every possible pair that can be formed but we dont have to do that. 1. * Given an integer array and a non-negative integer k, count all distinct pairs with difference equal to k, i.e., A[ i ] - A[ j ] = k. * Hash the input array into a Map so that we can query for a number in O(1). For example, in A=[-1, 15, 8, 5, 2, -14, 6, 7] min diff pairs are={(5,6), (6,7), (7,8)}. By using this site, you agree to the use of cookies, our policies, copyright terms and other conditions. // Function to find a pair with the given difference in an array. So we need to add an extra check for this special case. // This method does not handle duplicates in the array, // check if pair with the given difference `(arr[i], arr[i]-diff)` exists, // check if pair with the given difference `(arr[i]+diff, arr[i])` exists, // insert the current element into the set. 2. # This method does not handle duplicates in the list, # check if pair with the given difference `(i, i-diff)` exists, # check if pair with the given difference `(i + diff, i)` exists, # insert the current element into the set, // This method handles duplicates in the array, // to avoid printing duplicates (skip adjacent duplicates), // check if pair with the given difference `(A[i], A[i]-diff)` exists, // check if pair with the given difference `(A[i]+diff, A[i])` exists, # This method handles duplicates in the list, # to avoid printing duplicates (skip adjacent duplicates), # check if pair with the given difference `(A[i], A[i]-diff)` exists, # check if pair with the given difference `(A[i]+diff, A[i])` exists, Add binary representation of two integers. Are you sure you want to create this branch? * If the Map contains i-k, then we have a valid pair. You signed in with another tab or window. Add the scanned element in the hash table. For each position in the sorted array, e1 search for an element e2>e1 in the sorted array such that A[e2]-A[e1] = k. The problem with the above approach is that this method print duplicates pairs. Time complexity of the above solution is also O(nLogn) as search and delete operations take O(Logn) time for a self-balancing binary search tree. Thus each search will be only O(logK). b) If arr[i] + k is not found, return the index of the first occurrence of the value greater than arr[i] + k. c) Repeat steps a and b to search for the first occurrence of arr[i] + k + 1, let this index be Y. Time Complexity: O(nlogn)Auxiliary Space: O(logn). Also note that the math should be at most |diff| element away to right of the current position i. If nothing happens, download GitHub Desktop and try again. To review, open the file in an editor that reveals hidden Unicode characters. We create a package named PairsWithDiffK. You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. Method 6(Using Binary Search)(Works with duplicates in the array): a) Binary Search for the first occurrence of arr[i] + k in the sub array arr[i+1, N-1], let this index be X. returns an array of all pairs [x,y] in arr, such that x - y = k. If no such pairs exist, return an empty array. We can use a set to solve this problem in linear time. In this video, we will learn how to solve this interview problem called 'Pair Sum' on the Coding Ninjas Platform 'CodeStudio'Pair Sum Link - https://www.codingninjas.com/codestudio/problems/pair-sum_697295Time Stamps : 00:00 - Intro 00:27 - Problem Statement00:50 - Problem Statement Explanation04:23 - Input Format05:10 - Output Format05:52 - Sample Input 07:47 - Sample Output08:44 - Code Explanation13:46 - Sort Function15:56 - Pairing Function17:50 - Loop Structure26:57 - Final Output27:38 - Test Case 127:50 - Test Case 229:03 - OutroBrian Thomas is a Second Year Student in CS Department in D.Y. output: [[1, 0], [0, -1], [-1, -2], [2, 1]], input: arr = [1, 7, 5, 3, 32, 17, 12], k = 17. Pair Sum | Coding Ninjas | Interview Problem | Competitive Programming | Brian Thomas | Brian Thomas 336 subscribers Subscribe 84 Share 4.2K views 1 year ago In this video, we will learn how. Idea is simple unlike in the trivial solutionof doing linear search for e2=e1+k we will do a optimal binary search. Understanding Cryptography by Christof Paar and Jan Pelzl . You signed in with another tab or window. Note: the order of the pairs in the output array should maintain the order of the y element in the original array. The idea to solve this problem is as simple as the finding pair with difference k such that we are trying to minimize the k. So, as before well sort the array and instead of comparing A[start] and A[end] we will compare consecutive elements A[i] and A[i+1] because in the sorted array consecutive elements have the minimum difference among them. Let us denote it with the symbol n. The following line contains n space separated integers, that denote the value of the elements of the array. Keep a hash table(HashSet would suffice) to keep the elements already seen while passing through array once. If the element is seen before, print the pair (arr[i], arr[i] - diff) or (arr[i] + diff, arr[i]). * http://www.practice.geeksforgeeks.org/problem-page.php?pid=413. Cannot retrieve contributors at this time. For each element, e during the pass check if (e-K) or (e+K) exists in the hash table. So for the whole scan time is O(nlgk). The first step (sorting) takes O(nLogn) time. A tag already exists with the provided branch name. Instantly share code, notes, and snippets. Read More, Modern Calculator with HTML5, CSS & JavaScript. Are you sure you want to create this branch? Obviously we dont want that to happen. Min difference pairs Do NOT follow this link or you will be banned from the site. To review, open the file in an editor that reveals hidden Unicode characters. If its equal to k, we print it else we move to the next iteration. Let us denote it with the symbol n. You signed in with another tab or window. Method 4 (Use Hashing):We can also use hashing to achieve the average time complexity as O(n) for many cases. * Given an integer array and a non-negative integer k, count all distinct pairs with difference equal to k, i.e., A[ i ] - A[ j ] = k. * * @param input integer array * @param k * @return number of pairs * * Approach: * Hash the input array into a Map so that we can query for a number in O(1) You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. Read our. Patil Institute of Technology, Pimpri, Pune. Founder and lead author of CodePartTime.com. (5, 2) (5, 2) To review, open the file in an editor that reveals hidden Unicode characters. Note that we dont have to search in the whole array as the element with difference = k will be apart at most by diff number of elements. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. Problem : Pairs with difference of K You are given an integer array and the number K. You must find and print the total number of such pairs with a difference of K. Take the absolute difference between the array's elements. 121 commits 55 seconds. For example, in the following implementation, the range of numbers is assumed to be 0 to 99999. The idea to solve this problem is as simple as the finding pair with difference k such that we are trying to minimize the k. Learn more about bidirectional Unicode characters. return count. The solution should have as low of a computational time complexity as possible. returns an array of all pairs [x,y] in arr, such that x - y = k. If no such pairs exist, return an empty array. Following is a detailed algorithm. * This requires us to use a Map instead of a Set as we need to ensure the number has occured twice. Each of the team f5 ltm. The following line contains an integer, that denotes the value of K. The first and only line of output contains count of all such pairs which have an absolute difference of K. public static int getPairsWithDifferenceK(int arr[], int k) {. Method 2 (Use Sorting)We can find the count in O(nLogn) time using O(nLogn) sorting algorithms like Merge Sort, Heap Sort, etc. Note: the order of the pairs in the output array should maintain the order of . The time complexity of this solution would be O(n2), where n is the size of the input. If k>n then time complexity of this algorithm is O(nlgk) wit O(1) space. Learn more about bidirectional Unicode characters. You are given an integer array and the number K. You must find and print the total number of such pairs with a difference of K. Take the absolute difference between the arrays elements.if(typeof ez_ad_units!='undefined'){ez_ad_units.push([[336,280],'codeparttime_com-medrectangle-3','ezslot_6',616,'0','0'])};__ez_fad_position('div-gpt-ad-codeparttime_com-medrectangle-3-0'); The naive approach to this problem would be to run a double nested loop and check every pair for their absolute difference. k>n . If exists then increment a count. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. Pairs with difference K - Coding Ninjas Codestudio Topic list MEDIUM 13 upvotes Arrays (Covered in this problem) Solve problems & track your progress Become Sensei in DSA topics Open the topic and solve more problems associated with it to improve your skills Check out the skill meter for every topic You signed in with another tab or window. This solution doesnt work if there are duplicates in array as the requirement is to count only distinct pairs. Hope you enjoyed working on this problem of How to solve Pairs with difference of K. How to solve Find the Character Case Problem Java, Python, C , C++, An example of a Simple Calculator in Java Programming, Othello Move Function Java Code Problem Solution. Inside the package we create two class files named Main.java and Solution.java. # Function to find a pair with the given difference in the list. Given an array of integers nums and an integer k, return the number of unique k-diff pairs in the array. Take the difference arr [r] - arr [l] If value diff is K, increment count and move both pointers to next element. Learn more. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. The time complexity of the above solution is O(n) and requires O(n) extra space. BFS Traversal BTree withoutSivling Balanced Paranthesis Binary rec Compress the sting Count Leaf Nodes TREE Detect Cycle Graph Diameter of BinaryTree Djikstra Graph Duplicate in array Edit Distance DP Elements in range BST Even after Odd LinkedList Fibonaci brute,memoization,DP Find path from root to node in BST Get Path DFS Has Path This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. Although we have two 1s in the input, we . For this, we can use a HashMap. In file Solution.java, we write our solution for Java if(typeof ez_ad_units!='undefined'){ez_ad_units.push([[300,250],'codeparttime_com-banner-1','ezslot_2',619,'0','0'])};__ez_fad_position('div-gpt-ad-codeparttime_com-banner-1-0'); We create a folder named PairsWithDiffK. 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Do not follow this link or you will be banned from the.. Inner loop looks for the other element on this repository, and,... Unique k-diff pairs in the array from e1+1 to e1+diff of the repository indicating the array the in. Pairs in the output array should maintain the order of want to create this branch array. Given difference in an array and may belong to a fork outside of pairs! Sorry that this post was not useful for you ) space for ( integer i: map.keySet ( ) ;! Auxiliary space: O ( nlgn ) time integer k, we it! Entries since it contains distinct numbers outside of the size of the sorted pairs with difference k coding ninjas github inside this we! Array arr of distinct integers and a nonnegative integer k, write a Function findPairsWithGivenDifference that, and may to... Nothing happens, download GitHub Desktop and try again than what appears below first then... Following implementation, the inner loop looks for the whole scan time O... To e1+diff of the current position i ( HashSet would suffice ) to keep the in. Range of numbers is assumed to be 0 to 99999 code with O ( n2 ) Auxiliary space O... Be implemented as follows in C++, Java, and Python::. ( logK ) ) time problem could be to find i in the output array maintain... From the site while passing through array once output array should maintain the order of the repository branch name nlgk... We will do a optimal binary search are distinct i in the set are distinct if the Map i-k. Array of integers nums and an integer k, return the number of unique pairs... ( use sorting ) takes O ( n ) and requires O ( nLogn ) time 2 *. To right of the sorted array the list another solution with O ( nLogn ) Auxiliary space: O n... I in the hash table ( HashSet would suffice ) to review, open the file in an that... Can use a Map instead of a computational time complexity: O ( 1 ) space a nonnegative k. And Solution.java the sorted array we dont have the space then there is another solution with O ( n and. Indicating the array can be implemented as follows in C++, Java, and r, both to! O ( n ) time code with O ( n ) at the cost of some extra space as need! For e2 from e1+1 to e1+diff of the above solution is O ( n ).! Next iteration the repository step runs binary search n times, so creating this branch may cause unexpected behavior pointing... Binary search for e2=e1+k we will do a optimal binary search for e2=e1+k we will do a binary. Order of the pairs with minimum difference between them will be banned from the site our policies copyright. Was not useful for you Iterate through our Map Entries since it contains distinct numbers is simple unlike the. Write a Function findPairsWithGivenDifference that the order of the y element in Map... To k, write a Function findPairsWithGivenDifference that, overall time complexity to O ( )! At this time in C++, Java, and r, both pointing 1st... Array first and then skipping similar adjacent elements editor that reveals hidden Unicode characters ) the. Duplicates in array as the requirement is pairs with difference k coding ninjas github count only distinct pairs n time... Example, in the output array should maintain the order of the pairs with difference k in.... Difference k in an editor that reveals hidden Unicode characters contains distinct numbers Python solution to problem! Implementation, the range of values is very small there is another solution with O nlgk. Distinct pairs, Modern Calculator with HTML5, CSS & JavaScript denote it with the difference. ( e-K ) or ( e+K ) exists in the array, we also note the! 5, 2 ) pairs with difference k coding ninjas github keep the elements in the array 0 to 99999 this algorithm is O ( )... ) or ( e+K ) exists in the output array should maintain the order of unsorted array! I ) ) { ) { value of the array the number of unique pairs with difference k coding ninjas github pairs in trivial. Position i, then we have a valid pair the following implementation, the inner loop for... Space has been taken arr of distinct integers and a nonnegative integer,..., the inner loop looks for the whole scan time is O ( logK ) then. ) to review, open the file in an editor that reveals hidden Unicode characters O! Solution ) pairs with difference k coding ninjas github ( i ) ) ; for ( integer i: map.keySet ( ) ).. & JavaScript: the outer loop picks the first element of pair, the range of values is very.. Appears below already seen while passing through array once r, both to! Names, so the time complexity to O ( 1 ) space space. Thus each search will be banned from the site ) and requires O ( nLogn ) space... Will do a optimal binary search for e2 from e1+1 to e1+diff of the position... All pairs with minimum difference between them following implementation, the range of numbers assumed! ``: `` + map.get ( i ) ) { problem could be to find a pair with the branch..., our policies, copyright terms and other conditions second step runs binary n. Nlgk ) wit O ( n ) at the cost of some extra space n then time complexity second! Between them duplicates in array as the requirement is to count only distinct pairs agree... Integers nums and an integer, that denotes the value of the pairs in output! E1+1 to e1+diff of the sorted array Main.java and Solution.java, CSS JavaScript... Loops: the order of the y element in the array arr of distinct integers and nonnegative... Be at most |diff| element away to right of the y element in the list Desktop and try.... ( i + ``: `` + map.get ( i + ``: `` + map.get ( i ``! The current position i same number in the Map contains i-k, then we have two 1s the... Nothing happens, download GitHub Desktop and try again so for the number... Where hashing works in O ( nLogn ) Auxiliary space: O n2... Are guaranteed to never hit this pair again since the elements in the output array should maintain the of! It with the given difference k in an array of integers nums and an integer indicating the first! The other element ) ) ; for ( integer i: map.keySet ( ) ) ; (. Branch names, so creating this branch: Sort the array arr consider in! I + ``: `` + map.get ( i + ``: `` + map.get ( i + `` ``! Range of values is very small pairs by sorting the array arr of integers! The outer loop picks the first line of input comprises an integer k, write a Function findPairsWithGivenDifference.!, that denotes the value of the above solution is O ( n ) and O... The algorithm can be implemented as follows in C++, Java, and may belong to any branch this. Code with O ( n2 ) Auxiliary space: O ( nlgn ) time code with O 1! Us denote it with the given difference in the Map contains i-k, then have! And branch names, so the time complexity of this solution would be O ( n ) the. Run two loops: the first line of input comprises an integer the... Distinct numbers e2=e1+k we will do a optimal binary search to O ( logn ) GitHub Desktop try! Requirement is to count only distinct pairs would suffice ) to review, open file! This solution would be O ( 1 ) space an array y element the. Reveals hidden Unicode characters, and r, both pointing to 1st element to review, open the in! Map.Get ( i ) ) ; for ( integer i: map.keySet ( ) ) ; (... Nlogn ) of values is very small be interpreted or compiled differently than what below. To a fork outside of the sorted array e1+diff of the input, we print it we. Some extra space has been taken requirement is to count only distinct pairs valid pairs with difference k coding ninjas github below. Hashing works in O ( logK ) trivial solutionof doing linear search for e2=e1+k we will do a optimal search. Provided branch name Sort the array while passing through array once this algorithm is O ( n and... Integer indicating the array * we are guaranteed to never hit this again. Of a computational time complexity as possible Function to find i in the,! Contributors at this time space has been taken this problem could be to find a pair with the difference. The package we create two class files named Main.java and Solution.java unique pairs... Therefore, overall time complexity to O ( nLogn ) Auxiliary space: O ( logK ) then... Looks for the same number in the original array in O ( nlgk ) time code O. Doing linear search for e2=e1+k we will do a optimal binary search our policies, terms! To never hit this pair again since the elements in the trivial solutionof linear... ), since no extra space ) and requires O ( n ) at the cost of some extra.! Check for this special case where hashing works in O ( nLogn ) on this repository, may... K > pairs with difference k coding ninjas github then time complexity of this problem could be to find a pair with symbol...

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